1-4*[(k+2)x^2]*-3=0

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Solution for 1-4*[(k+2)x^2]*-3=0 equation:


Simplifying
1 + -4[(k + 2) * x2] * -3 = 0

Reorder the terms:
1 + -4[(2 + k) * x2] * -3 = 0

Reorder the terms for easier multiplication:
1 + -4[x2(2 + k)] * -3 = 0
1 + -4[(2 * x2 + k * x2)] * -3 = 0

Reorder the terms:
1 + -4[(kx2 + 2x2)] * -3 = 0
1 + -4[(kx2 + 2x2)] * -3 = 0

Reorder the terms for easier multiplication:
1 + -4 * -3[kx2 + 2x2] = 0

Multiply -4 * -3
1 + 12[kx2 + 2x2] = 0
1 + [kx2 * 12 + 2x2 * 12] = 0
1 + [12kx2 + 24x2] = 0

Solving
1 + 12kx2 + 24x2 = 0

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + 12kx2 + -1 + 24x2 = 0 + -1

Reorder the terms:
1 + -1 + 12kx2 + 24x2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 12kx2 + 24x2 = 0 + -1
12kx2 + 24x2 = 0 + -1

Combine like terms: 0 + -1 = -1
12kx2 + 24x2 = -1

Add '-24x2' to each side of the equation.
12kx2 + 24x2 + -24x2 = -1 + -24x2

Combine like terms: 24x2 + -24x2 = 0
12kx2 + 0 = -1 + -24x2
12kx2 = -1 + -24x2

Divide each side by '12x2'.
k = -0.08333333333x-2 + -2

Simplifying
k = -0.08333333333x-2 + -2

Reorder the terms:
k = -2 + -0.08333333333x-2

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